# Just How Hard Is Thor’s Battle Chain Workout?

For the reason that velocity is outlined because the time-rate of change of place, the slope of this plot ought to give the speed. That places this wave pace at 2.85 m/s, which is fairly near the theoretical prediction. I am proud of that.

However what if I wish to take a look at the pace of a wave in a large steel chain, as an alternative of a string of beads? I really haven’t got considered one of these items mendacity round—and I most likely could not transfer it anyway. So let’s construct a computational mannequin.

This is my thought: I will let the chain be made from a bunch of level lots linked by springs, like this:

A spring exerts a pressure that’s proportional to the quantity of stretch (or compression). This makes them very helpful. Now I can take a look at the positions of all of the lots on this mannequin and decide how a lot every connecting spring is stretched. With that, it is a pretty easy step to calculate the web pressure of every mass.

After all, with the web pressure I can discover the acceleration for every bit utilizing Newton’s second regulation: Finternet = ma. The issue with this spring pressure is that it isn’t fixed. Because the lots transfer, the stretch of every spring modifications and so does the pressure. It’s not a simple downside. However there’s a answer that makes use of a little bit of magic.

Think about that we calculate the forces on every mass of this modeled collection of springs. Now suppose that we simply think about a really quick interval of time, like possibly 0.001 seconds. Throughout this interval, the beads do certainly transfer—however not that a lot. It isn’t an enormous stretch (pun supposed) to imagine that the spring forces do not change. The shorter the time interval, the higher this assumption turns into.

If the pressure is fixed, it isn’t too tough to search out the change in velocity and place of every mass. Nevertheless, by making the issue easier, we have simply made extra issues. With a purpose to mannequin the movement of the beaded string after simply 1 second, I would want to calculate the movement for 1,000 of those time intervals (1/0.001 = 1,000). Nobody needs to do this many calculations—so we are able to simply make a pc do it. (That is the primary thought behind a numerical calculation.)